Steiner circumellipse, construction, geometry, triangle, Heisss, Würzburg

The Steiner Circumellipse -

Two Simple Methods of Construction

 

by

Markus Heisss

2019/2022, Würzburg, Bavaria

 

   The copying of the following graphics is allowed, but without changes.

  [To get a bigger picture, please click it with the cursor.]

   

A Short Introduction to the Topic:

 

First step: Construct a circle at centroid G

with the radius of the minor semi-axis.

Now draw three lines parallel to the major semi-axis of the ellipse

through the vertices of the triangle.

Three of the intersections form an equilateral triangle.

See next figure:

 

Steiner circumellipse, ellipse, affine transformation

 Fig. 1: Affine transformation of the Steiner circumellipse

 

Here we have a case of an affine transformation,

which is described in detail in Roger A. Johnson's important classic book

"Advanced Euclidean Geometry"

in the chapter "Vertical Projections" (p. 290ff).

 

 

Strongly simplified: Think a cut along the major semi-axis

vertical to the plane of the ellipse,

 as shown in the next figure:

 

 Fig. 2: Vertical cut through the Steiner circumellipse

 

Simply said: Project the Steiner circumellipse so,

that it becomes a circle, than the original triangle ABC

becomes an equilateral triangle.

The angle Φ between both planes can be simply calculated.

(The formula is shown in the graphic above.)

 

 

There is also a connection of this equilateral triangle to the Napoleon triangles.

(More advance information to the Napoleon triangles you get here:

[https://napoleon-triangles.jimdofree.com/]

 

Theorem:

The outer Napoleon triangle and the equilateral triangle A'B'C',

which is a vertical projection of the Steiner circumellipse,

are homothetic (Heisss, August 2019).

 

("Homothetic" means, that the triangles are similar

and have the same orientation.

The respective sides of both triangles are therefore parallel).

 

This is shown in the next graphic:

 

outer Napoleon triangle and Steiner circumellipse; Theorem by Heisss, Würzburg

Fig. 3: Outer Napoleon triangle and into a circle transformed Steiner circumellipse

 

It exists also a counterpart to the inner Napoleon triangle,

because there are three alternative intersections of the parallel lines with the projected circle.

These three points of intersection form another equilateral triangle.

 

Theorem:

The inner Napoleon triangle and the equilateral triangle A''C''B'',

which is a vertical projection of the Steiner circumellipse,

are homothetic (Heisss, August 2019).

 

This is shown in the following graphic:

 

inner Napoleon triangle and transformed Steiner circumellipse; with parallel lines; by Heisss

Fig. 04: Inner Napoleon triangle and into a circle transformed Steiner circumellipse

 

Both theorems together lead to the very simple and "real" method of construction

of the axes of symmetry of the Steiner circumellipse.

 

As shown above yet, but again:

 

Steiner circumellipse, construction, problem, geometry, triangle, Heisss, Würzburg, Germany

Fig. 5: Fast Method of Construction of the Steiner circumellipse

 

 ... and in comparison a former method of construction:
 

Geometry, ellipse, construction

Fig. 5a: Former Method of Construction of the Steiner Circumellipse with a Disadvantage

 


 

... And Another Method of Construction

 

The following explanation is illustrated with an example:

 

Formulas and calculation of the Steiner circumellipse
Formulas and calculation of the semiaxes of the Steiner circumellipse

 

You can copy these formulas:

 k1=a^2+b^2+c^2, k2=a^2*b^2+b^2*c^2+c^2*a^2, k3=a^4+b^4+c^4, k4=(k3-k2)^(1/2), k5=k1/((2*k2-k3)^(1/2))

ae=1/3*((k1+2*k4)^(1/2)), be=1/3*((k1-2*k4)^(1/2)), tanPhi=1/3*(k5-((k5^2-3)^(1/2)))

 

Construction step by step:

 [Note: Of course it is no pure method of construction with only straight edge and compass.

But the result in the end is exact!]

 

1st) Construct the triangle ABC and its centroid G.

 

2nd) Draw a straight line through one of the vertices of the triangle

with the calculated angle φ to the inner side of the triangle.

The intersection of this line with the perpendicular bisector

of the respective triangle side is the Point P.

 

3rd) The line GP is one of both axes of symmetry of the Steiner circumellipse.

The second axis of symmetry is perpendicular in the centroid.

 

4th) Transfer the calculated lengths of the semi-axes ae and be

from the centroid to the respective axis of symmetry of the Steiner circumellipse.

 

5th) These four points of intersection Qn and the three vertices of the triangle

lie all on the Steiner circumellipse ... which are more than enough points for a drawing.

 

Steiner ellipse, circumellipse

Fig. 06:  Alternative construction of the Steiner circumellipse

 

By the way: The intersection of the circumcircle of the triangle with the Steiner circumellipse

leads to a further point, the so-called "Steiner point" S.

(... as shown above)

 

Note: The Steiner point S is the Kimberling center X99.

A table of all important points of a triangle you can find here:

[https://faculty.evansville.edu/ck6/encyclopedia/ETC.html]

Note: Further important information to the Steiner circumellipse

you will find at the following website:

[http://mathworld.wolfram.com/SteinerCircumellipse.html]

 

 

There is also a so-called "Steiner inellipse".

See next graphic:

 

steiner inellipse

 Fig. 7: The Steiner inellipse

 

You can see that the respective distances

have always half the lengths of those of the circumellipse.

 

Further important information to the Steiner inellipse

you will find here:

[http://mathworld.wolfram.com/SteinerInellipse.html]

Closing Note:

The shown "alternative method of construction"

(--which is, as said before, no pure construction--) uses the discovery,

that the intersections of the three McCay circles

with the respective perpendicular bisectors of the triangle's sides

form two collinearities, which are identical

with the axes of symmetry of the Steiner circumellipse.

 

Application:

 With the help of these two methods of construction

it is easy to construct the three McCay circles of a given triangle!

 

More information in detail you will find here:

[McCay circles]

 

... And further relationships to the Steiner circumellipse here:

[Napoleon triangles]

[Frégier's theorem]

********************************

Postscript: 2. April 2022

 

... and another discovery:

 

Steiner circumellipse, Napoleon triangle, circle, theorem, geometry

Fig. 8: Relationship between the Steiner circumellipse and the two Napoleon circles

theorem, Napoleon circles, Steiner circumellipse

 

Please note also the simple relationships between the radii of the Napoleon circles

and the semi-axes of the Steiner circumellipse!

 

**************************************

[Proofs]

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Are you interested in my other geometrical discoveries?

[here]